k^2x^2-k(2k+1)x+(2k^2+k-6)=0

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Solution for k^2x^2-k(2k+1)x+(2k^2+k-6)=0 equation: 


Simplifying
k2x2 + -1k(2k + 1) * x + (2k2 + k + -6) = 0

Reorder the terms:
k2x2 + -1k(1 + 2k) * x + (2k2 + k + -6) = 0

Reorder the terms for easier multiplication:
k2x2 + -1k * x(1 + 2k) + (2k2 + k + -6) = 0

Multiply k * x
k2x2 + -1kx(1 + 2k) + (2k2 + k + -6) = 0
k2x2 + (1 * -1kx + 2k * -1kx) + (2k2 + k + -6) = 0
k2x2 + (-1kx + -2k2x) + (2k2 + k + -6) = 0

Reorder the terms:
k2x2 + -1kx + -2k2x + (-6 + k + 2k2) = 0

Remove parenthesis around (-6 + k + 2k2)
k2x2 + -1kx + -2k2x + -6 + k + 2k2 = 0

Reorder the terms:
-6 + k + -1kx + 2k2 + -2k2x + k2x2 = 0

Solving
-6 + k + -1kx + 2k2 + -2k2x + k2x2 = 0

Solving for variable 'k'.

The solution to this equation could not be determined.

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